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弗雷格迷题的无解性 |
Insolubility of Freges Puzzle |
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DOI: |
中文关键词: 弗雷格迷题 指称 涵义 语义学 认知价值 |
英文关键词: Key words: Freges puzzle reference sense semantics cognitive value |
基金项目:国家社科基金重大项目(12&ZD119) |
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中文摘要: |
为真的同一陈述句a=b与a=a在认知价值上有区别。这种区别的根源是什么?弗雷格在《论涵义与指称》中试图从语义的角度来解释。这个问题后来被称作“弗雷格迷题”。其他的哲学家或是从语义方面继承弗雷格的思想,或是从语形方面来解决它。但已有的这两方面的考虑都不能解决弗雷格迷题。若某种语义理论能够解决弗雷格迷题,其自身所存在着的“高阶”弗雷格迷题将迫使它或者不能解决后者,或者会导致不同的符号无法被用于同一陈述。另一方面,从语形出发解释弗雷格迷题的方案,并不比直接规定“这两个表达式的认知价值不同”有更多的优势。从这个意义而言,弗雷格迷题是不可解的。 |
英文摘要: |
There are cognitive differences between equalities “a=b” and “a=a”. What is the source of these differences? Frege tried to interpret it semantically in his On Sense and Reference. Afterwards this problem was called “Freges Puzzle”. Other Philosophers tried to answer it. They either treated it semantically by inheriting Frege’s method, or treated it syntactically. But so far none of them solved Freges puzzle. If there were some semantic theories which were able in solving Freges puzzle, their intrinsic “higher-order” Freges puzzles would still be insoluble, or it would force that distinct symbols would never be used on equalities. On the other hand, solving Freges puzzle syntactically is not better than merely demanding “these two expressions are cognitively different”. On this sense, Freges puzzle is insoluble. |
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